URL Query String in GO
Extract the query string portion of a URL (everything between `?` and `#` or end-of-string).
Try it in the GO tester →Pattern
regexGO
\?([^#\s]+) (flags: g)Go (RE2) code
goGo
package main
import (
"fmt"
"regexp"
)
func main() {
re := regexp.MustCompile(`\?([^#\s]+)`)
input := `https://example.com/page?utm_source=google&id=42`
for _, match := range re.FindAllString(input, -1) {
fmt.Println(match)
}
}Uses `regexp.MustCompile` (panics on bad patterns at startup) and `FindAllString` for all matches.
How the pattern works
\? matches the literal question mark. ([^#\s]+) captures everything up to (but not including) a `#` (fragment) or whitespace (URL boundary). Use URL parsing libraries for production, but this regex is handy for quick log scraping.
Examples
Input
https://example.com/page?utm_source=google&id=42Matches
?utm_source=google&id=42
Input
/api?token=abc#sectionMatches
?token=abc
Input
no query string hereNo match
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