URL Query String in JS
Extract the query string portion of a URL (everything between `?` and `#` or end-of-string).
Try it in the JS tester →Pattern
regexJS
\?([^#\s]+) (flags: g)JavaScript / ECMAScript code
jsJavaScript
const re = new RegExp("\\?([^#\\s]+)", "g");
const input = "https://example.com/page?utm_source=google&id=42";
const matches = [...input.matchAll(re)];
console.log(matches.map(m => m[0]));Uses `String.prototype.matchAll` for global iteration (Node 12+ / all modern browsers).
How the pattern works
\? matches the literal question mark. ([^#\s]+) captures everything up to (but not including) a `#` (fragment) or whitespace (URL boundary). Use URL parsing libraries for production, but this regex is handy for quick log scraping.
Examples
Input
https://example.com/page?utm_source=google&id=42Matches
?utm_source=google&id=42
Input
/api?token=abc#sectionMatches
?token=abc
Input
no query string hereNo match
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