URL Path Segment in PY
Match individual `/segment` parts of a URL path, capturing each one.
Try it in the PY tester →Pattern
regexPY
\/([^\/?#\s]+) (flags: g)Python (re) code
pyPython
import re
pattern = re.compile(r"\/([^\/?#\s]+)")
input_text = "/users/42/posts?page=2"
for m in pattern.finditer(input_text):
print(m.group(0))Stdlib `re` module — no third-party dependency. Works on Python 3.6+.
How the pattern works
\/ matches the literal slash. ([^\/?#\s]+) captures one or more characters that aren't a slash, question mark, hash, or whitespace — i.e. one path segment. Useful for breaking apart a URL into its component pieces.
Examples
Input
/users/42/posts?page=2Matches
/users/42/posts
Input
/api/v1/healthMatches
/api/v1/health
Input
no/pathNo match
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