Numbersflags: g

Binary Number Literal

Match binary number literals like `0b1010` or `0B11110000`.

Try it in RegexPro →

Available in

JSSupported

JavaScript / ECMAScript

Browser-native RegExp. Default if you don't pick.

PYSupported

Python (re)

CPython stdlib `re`. Unicode-aware `\w` and `\d` by default.

GOSupported

Go (RE2)

Linear-time matching. No backreferences or lookarounds.

Pattern

regexengine-agnostic
\b0[bB][01]+\b   (flags: g)

Raw source: \b0[bB][01]+\b

How it works

\b is a word boundary so we don't match inside identifiers. 0[bB] matches the literal prefix (case-insensitive on the b). [01]+ matches one or more binary digits. Trailing \b prevents matching into adjacent word characters.

Examples

Input

Mask = 0b1010, halfbyte = 0B1111

Matches

  • 0b1010
  • 0B1111

Input

for i := 0; i < 0b1000; i++

Matches

  • 0b1000

Input

no binary here

No match

—

Common use cases

  • •Source-code analysis for bitmask literals
  • •Embedded / firmware tooling
  • •Educational / tutorial parsing
  • •Linting rules for magic numbers
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